In an old mechanical child\'s game, a small block is launched from a spring comp
ID: 1684192 • Letter: I
Question
In an old mechanical child's game, a small block is launched from a spring compressed by a player. The object is to just barely get the block up a short ramp. The spring has a force constant of 650 N/m; the block has a mass of 0.22 kg. During a particular player's turn, the spring is compressed 3.2 cm with the block at rest. It is then released. The game's surface is highly polished; ignore the effects of friction.a) after release, the block moves away from the spring and slides smoothly along the horizontal track. what is the velocity after leaving the spring (v1)? b) then, it slides 24 cm along a ramp inclined at 22 degrees. what is the velocity after going up this ramp (V2)? a) after release, the block moves away from the spring and slides smoothly along the horizontal track. what is the velocity after leaving the spring (v1)? b) then, it slides 24 cm along a ramp inclined at 22 degrees. what is the velocity after going up this ramp (V2)?
Explanation / Answer
a. use this potential energy equation and energy conservation. 1/2 (ks^2)=1/2 (mv^2) k is spring constant s is the displacement or how much the spring is compressed. and m is mass, v is speed. plug in everything and solve for v, u get 1.739m/s b. Use energy conservation and potential energy equation too. But make sure ur only doing the VERTICAL part. use this equation 1/2 (mv^2)-mgh=1/2 (mvf^2) m is mass, v is initial speed. g is gravity, h is height of the ramp. vf is final velocity. h=0.24sin 22. It is the ACTUAL height, not the length of the ramp. g is 9.8. v=1.739Sin 22. Cuz you only want the vertical part. Plug in everythign adn solve for vf you get -1.15m/s This means that it won't go up the ramp and keep going. It will only go up the ramp and then go down again.
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