Your telescope has a 800 {\ m mm}-focal-length objective and a 28 {\ m mm}-focal

Question

Your telescope has a 800 { m mm}-focal-length objective and a 28 { m mm}-focal-length eyepiece. One evening you decide to look at the full moon, which has an angular size of 0.52^circ when viewed with the naked eye. What angle (in degrees) does the image of the moon subtend, when you look at it through your telescope? Suppose you decide to take a photograph of the moon using your telescope. You position film so that it captures the image produced by the objective lens. What is the diameter of that image?

Explanation / Answer

angular size of the moon = .52 degrees Image projected: angle = d/fo d = fo * angle = 800 mm * (.52)*(p/180) = 7.25 mm

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