A current carrying wire of length 50 cm is positioned perpendicular to a uniform

Question

A current carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. I the current is 10.0 A and it is determined that there is a resultant force of 3.0 N on the wire due to the interaction of the current and field, what is the magnetic fiels strength?

a. 0.6 T
b. 1.50 T
c. 1.85 x10 3 T d.6.7 x 10 3 T A current carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. I the current is 10.0 A and it is determined that there is a resultant force of 3.0 N on the wire due to the interaction of the current and field, what is the magnetic fiels strength?

a. 0.6 T
b. 1.50 T
c. 1.85 x10 3 T d.6.7 x 10 3 T

Explanation / Answer

The magnetic force is F = BIL The strength of the magnetci field is B = F/(IL) = (3.0 N)/((10.0 A)(0.50 m)) = 0.6 T

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