The imaging drum of a photocopier is positively charged to attract negatively ch
ID: 1684919 • Letter: T
Question
The imaging drum of a photocopier is positively charged to attract negatively charged toner particles. Near the surface of the drum, its electric field has magnitude 1.70 x 10^5 N/C. A toner particle is to be attracted to the drum with a force that is 7 times the weight of the particle.(a) What must be the ratio of the mass of a toner particle to the magnitude of its net charge?
(b) If the toner particles are made of carbon (atomic number 6, atomic mass 12.0 g/mol), how many carbon atoms are there for each excess electron on a toner particle?
Explanation / Answer
The force experienced by the toner particle in the field E=1.70X10^5 N/c is F=Eq Where E is the applied field q is the charge of the toner particle Let m be the mass of the toner particle Weight of the toner particle is W=mg Where g is the acceleration due to gravity = 9.8 m/ s^2 (A) Given that the required force is 7 times the weight i.e. F=7W Eq=7mg m/q = E/7g = (1.70X10^5 N/c)/7X(9.8 m/ s^2) =2478.13 kg/C (B) The number of atoms per mole of C is 6.023X10^23 12 gm of C contain 6.023X10^23 atoms Charge on 12 gm of C is q=(12X10^-3 kg)/(2478.13 kg/C) q=4.84X10^-6 C q=(3.022X10^13)e (e is the charge of electron) 6.023X10^23 atoms contains charge (3.022X10^13)e The number of atoms per e is 1.99X10^10
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