E(perpendicular)= 1/2*cos( k.r -wt) E(parallel)= b*cos( k.r -wt+f) **f is the ph

Question

E(perpendicular)= 1/2*cos(k.r-wt) E(parallel)= b*cos(k.r-wt+f)   **f is the phase
a) Determine the constants for a circular polarized beam incident on a half space angle of 45 degrees-plane of incidence is in the xz plane. The incident region has a refractive index of 1.5 and the transmitted region has a refractive index of 1.0. The wavelength of the ligth is 1µm, what is k, f ,b and give explicit forms of E(perpendicular) and E(parallel)
b) Compute the reflected and transmitted field components for the condition given in (a).
c) Determine the state of polarization for the reflected and transmitted waves (a).
Thanks a lot if you guys have any idea about the question.
E(perpendicular)= 1/2*cos(k.r-wt) E(parallel)= b*cos(k.r-wt+f)   **f is the phase
a) Determine the constants for a circular polarized beam incident on a half space angle of 45 degrees-plane of incidence is in the xz plane. The incident region has a refractive index of 1.5 and the transmitted region has a refractive index of 1.0. The wavelength of the ligth is 1µm, what is k, f ,b and give explicit forms of E(perpendicular) and E(parallel)
b) Compute the reflected and transmitted field components for the condition given in (a).
c) Determine the state of polarization for the reflected and transmitted waves (a).
Thanks a lot if you guys have any idea about the question. E(perpendicular)= 1/2*cos(k.r-wt) E(parallel)= b*cos(k.r-wt+f)   **f is the phase
a) Determine the constants for a circular polarized beam incident on a half space angle of 45 degrees-plane of incidence is in the xz plane. The incident region has a refractive index of 1.5 and the transmitted region has a refractive index of 1.0. The wavelength of the ligth is 1µm, what is k, f ,b and give explicit forms of E(perpendicular) and E(parallel)
b) Compute the reflected and transmitted field components for the condition given in (a).
c) Determine the state of polarization for the reflected and transmitted waves (a).

Explanation / Answer

Given incident angle ?_I =45^0 (a)For circularly polarised beam the amplitudes of two electric components are same
hence b =1/2
phase f= 90^0
propagation constant k=(2p/?)
k=(2*3.14)/10^-6 m k = 6.28*10^6 Frequency f = c/? Here c is light velocity f = (3*10^8 m/s)/(10^-6 m) f = 3*10^14 s the angular frequency is given by w = 2pf w=2*3.14*(3*10^14) w = 18.84 rad/s explicit forms of E(parellel) = (1/2)*cos(6.28*10^6 x-18.84 t+90^0) E(perpendicular) = (1/2)*cos(6.28*10^6 x-18.84 t) ------------------------------------------------------- (b)we know that Snell's law sin?_T/sin?_I = n-1/n-2 Here ?-T is tranmitted angle ?_I is incident angle n_1 is the refractive index of first medium n_2 is refractive index of a second medium the refracted angle

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.