This one has been bugging me all day. Can any one help? An astronaut on the star

Question

This one has been bugging me all day. Can any one help?

An astronaut on the starship Enterprise is on shore leave on a distant planet. She drops a rock from the top of a cliff and observes that it takes 2.532 seconds to reach the ground at the base of the cliff. She then takes another rock and throws it vertically upwards with a speed of 17.821 m/s so that it reaches a height h above the cliff before falling down to the ground at the base of the cliff near the first rock. The second rock takes a total time of 6.470 seconds to reach the ground, starting from the time it left the crewman

Explanation / Answer

Given: time = 2.532 seconds initial velocity = 0 (taken) solution for stone 1 from kinematic relations v = u+g_pt v = g_p 2.532----(1) for stone 2 v = 17.82+g_p(6.470)----(2) (2)-(1) -17.82 = g_p(3.94) g_p = -17.82/3.94 = -4.5 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.