http://session.masteringphysics.com/problemAsset/1072829/2/4.4.jpg A box with we

Question

http://session.masteringphysics.com/problemAsset/1072829/2/4.4.jpg

A box with weight w = 530 N is on a rough surface, inclined at an angle of 37 degrees. The box is kept from sliding down (in equilibrium) by means of an external force F. The other forces acting on the box are the normal and friction forces, denoted by n and f. A force diagram, showing the four forces that act on the box, is shown in Fig. 4.4. The magnitude of f is 110 N. The external force F is removed and the box accelerates. The magnitudes of the other forces are unchanged. The acceleration of the box is closest to:

2.3 m/s2
2.9 m/s2
4.8 m/s2
3.8 m/s2
5.8 m/s2

Explanation / Answer

the angle of incline plane ? = 37 when the box accelerates down then from Newton's law    Fnet = mgsin? - f
ma = Wsin? - f therefore the acceleration of the box    a = Wsin? - f /m = 530sin37 - 110 / 54kg = 3.8 m/s^2

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