In a rectangular coordinate system, a positive point charge q= 3.50 is placed at

Question

In a rectangular coordinate system, a positive point charge q= 3.50 is placed at the point x= 0.170 ,y=0 , and an identical point charge is placed at x=-0.170 , y=0. Find the x and y components and the magnitude and direction of the electric field at the following points.

A.) find the x and y components and magnitude and direction of the electric field at x=0.170m , y=-0.350m.
Ex, Ey?

B.)What is the net field

c.) what is the angle from the +x-axis In a rectangular coordinate system, a positive point charge q= 3.50 is placed at the point x= 0.170 ,y=0 , and an identical point charge is placed at x=-0.170 , y=0. Find the x and y components and the magnitude and direction of the electric field at the following points.

A.) find the x and y components and magnitude and direction of the electric field at x=0.170m , y=-0.350m.
Ex, Ey?

B.)What is the net field

c.) what is the angle from the +x-axis

Explanation / Answer

I'd draw a diagram, but cramster won't let me. But basically, you should draw a picture on an x-y coordinate system with the points q1 and q2, and the point where you want to find the net field. When you draw the vectors for the E fields, you'll find that E1 goes straight down, and E2 goes down and to the right, and should also be smaller (because q2 is further away then q1). Obviously, you need to split E2 into x and y components. Do this by saying E2sin(theta)=E2in the y, and e2cos(theta)=E2 in the x direction. Then, add the y component of E2 to E1, and use pythagorean theorem with E2 in the x direction to get the net field. The angle of this from the x-axis can be found in a similar way that theta was originally found for E2.

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