For the following question I need help with parts (b) and (c): A playground is o

Question

For the following question I need help with parts (b) and (c): A playground is on the flat roof of a city school, 5.4 m above the street below (see figure). The vertical wall of the building is h = 6.90 m high, forming a 1.5-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0°; above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. xf=xi+(vicos?)t xf=0+(vicos?)t vi=xf/cos?t vi=24/cos(53.0)2.20 vi=18.1 m/s
(b)Find the vertical distance by which the ball clears the wall. (c)Find the horizontal distance from the wall to the point on the roof where the ball lands.


A playground is on the flat roof of a city school, 5.4 m above the street below (see figure). The vertical wall of the building is h = 6.90 m high, forming a 1.5-m-high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of ? = 53.0°; above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. (a) Find the speed at which the ball was launched. xf=xi+(vicos?)t xf=0+(vicos?)t vi=xf/cos?t vi=24/cos(53.0)2.20 vi=18.1 m/s
(b)Find the vertical distance by which the ball clears the wall. (c)Find the horizontal distance from the wall to the point on the roof where the ball lands.

(b)Find the vertical distance by which the ball clears the wall. (c)Find the horizontal distance from the wall to the point on the roof where the ball lands.
(c)Find the horizontal distance from the wall to the point on the roof where the ball lands.

Explanation / Answer

b) known vi = 18.1 m/s y = vi*sin(A)*t - gt^2/2 where A = 53 degrees, t = 2.2 s, y = 8.13 m answer = y - h = 1.23 m c) h' = 5.4 m h' = vi*sin(A)*t' - gt'^2/2 4.9t'^2 - 14.46t' + 5.4 = 0 t' = 2.51 s x = vi*cos(A)*t' = 27.3 m answer = x - d = 3.3 m

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.