Question: How many degrees of freedom does a classical gas composed of 1023 poin

Question

Question: How many degrees of freedom does a classical gas composed of 1023 point particles have? My thoughts: I know that for a blackbody, U(v, t) = (8pv2/c3) * (avg. energy per degree of freedom)
But, is the number of deg. of freedom also (8pv2/c3) for a classical gas composed of said number of particles?
Question: How many degrees of freedom does a classical gas composed of 1023 point particles have? My thoughts: I know that for a blackbody, U(v, t) = (8pv2/c3) * (avg. energy per degree of freedom)
But, is the number of deg. of freedom also (8pv2/c3) for a classical gas composed of said number of particles?

Explanation / Answer

In 3 dimensions each classical identical particle associated with 6 degrees of freedom , 3 for position (x,y andz) and 3 for momentum (px, py, pz) . As each particle has 6 degrees of freedom , hence 1023 particles will have 1023*6=6138 degrees of freedom

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