A 1.50 kg steel block is at rest on a steel table. A horizontal string pulls on

Question

A 1.50 kg steel block is at rest on a steel table. A horizontal string pulls on the block. The coefficient of static friction of dry steel on steel is µ= .800, the coefficient of kinetic friction of dry steel on steel is µ= 0.600 , and the coefficient of kinetic friction of lubricated steel on steel is µ= 0.050. What is the minimum string tension needed to move the block? If the string tension is 20.0 N, what is the block's speed after moving 0.900 m? If the string tension is 20.0 N and the table is coated with oil, what is the block's speed after moving 0.900 m ?

Explanation / Answer

m = 1.50 kg, What is the minimum string tension needed to move the block? F = µmg, where µ = 0.800, so F = 11.8 N If the string tension is F = 20.0 N, what is the block's speed after moving d = 0.900 m? net force = F - µmg, acceleration a = F/m - µg, where µ = 0.600 speed = v, v^2 = 2ad v = sqrt(2ad) = sqrt[2d*(F/m - µg)] = 3.66 m/s If the string tension is F = 20.0 N and the table is coated with oil, what is the block's speed after moving d = 0.900 m ? net force = F - µmg, acceleration a = F/m - µg, where µ = 0.050 speed = v, v^2 = 2ad v = sqrt(2ad) = sqrt[2d*(F/m - µg)] = 4.81 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.