Three forces act on a particle that moves with a constant velocity v = 2m/s x -

Question

Three forces act on a particle that moves with a constant velocity v = 2m/s x - 7m/s y. Two of the forces acting on this particle are F1 = -5.0N x + -4.0N y + 3.0N z and F2 = = 7.0N x + -4.0N y + -9.0N z. What is the magnitude of the third force? the x, y and z refer to the axis the amount is on. Im not sure how to approach this at all.. any help? Three forces act on a particle that moves with a constant velocity v = 2m/s x - 7m/s y. Two of the forces acting on this particle are F1 = -5.0N x + -4.0N y + 3.0N z and F2 = = 7.0N x + -4.0N y + -9.0N z. What is the magnitude of the third force? the x, y and z refer to the axis the amount is on. Im not sure how to approach this at all.. any help?

Explanation / Answer

Three forces are acting on a particle, as a result of these three forces the particle is moving with constant velocity. So acceleration of the particle is zero. Then the net force acting on the particle is zero. Therefore F1 + F2 + F3 = 0 -5.0N x + -4.0N y + 3.0N z + 7.0N x + -4.0N y + -9.0N z + F3 = 0 F3 = (-2.0N)x + (8.0N)y + (6.0N)z

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