What is the normal force exerted on the mower by the lawn? Express your answer u

Question

What is the normal force exerted on the mower by the lawn? Express your answer using two significant figures. 1. Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s^2 . For the apparatus shown in the figure , what is the minimum value of the coefficient of static friction between the block ( m3 ) and the table that would keep the system at rest if m1 = 0.27 kg , m2 = 0.52 kg , and m3 = 0.75 kg ? 2. Unless otherwise stated, all objects are located near the Earth's surface, where g = 9.80 m/s^2 .A girl pushes a 26 kg lawn mower as shown in the figure .a)If F = 26 N and theta = 31 degree what is the acceleration of the mower? Ignore friction. Express your answer using two significant figures. b) What is the normal force exerted on the mower by the lawn? Express your answer using two significant figures.

Explanation / Answer

The pulleys redirect the y direction forces in the x direction. So the gravitational force on 1 pulls in the -x direction on block 3, gravitation force on 2 pulls in the positive x direction on block 3, and the gravitational force times the static friction coefficient resists the movement so is directed in the -x direction. Therefore: SFx = m2g-µsm3g-m1g=0 (.52)(9.8)-µs(.75)(9.8)-(.27)(9.8)=0 µs=.33 SFx = m2g-µsm3g-m1g=0 (.52)(9.8)-µs(.75)(9.8)-(.27)(9.8)=0 µs=.33 SFx = m2g-µsm3g-m1g=0 (.52)(9.8)-µs(.75)(9.8)-(.27)(9.8)=0

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