An airplane flies from Chicago to New Orleans (a distance of 1500 km) in the mor

Question

An airplane flies from Chicago to New Orleans (a distance of 1500 km) in the morning, then immediately returns to Chicago. The speed of the plane relative to the air is 239 m/s. The wind is blowing at 46 m/s from west to east, so it is perpendicular to the line that connects the two cities.
(a) What is the average speed of the plane relative to the ground on the way to New Orleans?
_______m/s

(b) What is the average speed relative to the ground on the way back to Chicago?
________m/s

(c) What is the average speed for the entire trip?
_________m/s

Explanation / Answer

0 = - Vpw cos ? + Vwg cos? = Vwg/Vpw = 46/239    ? = 78.9 deg now the speed Vpg = Vpw sin? = 239sin78.9 =234.5 m/s (a) The speed of the plane wrt ground    Vpg = 234.5 m/s (b) The relative speed plane in return Vpg = 234.5 m/s
(c) The avg speed for the entire trip
   V = 2(234.5)(234.5) / 2(234.5)           = 234.5 m/s

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