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B-->C-->D A--> E--->G--->H. H shows feedback inhibition of A. What initially hap

ID: 169494 • Letter: B

Question

B-->C-->D
A--> E--->G--->H.   
H shows feedback inhibition of A. What initially happens to H if the enzymes that catalyses B-- -> C is inhibited? What happens to A as a result? What is the final effect on A? B-->C-->D
A--> E--->G--->H.   
H shows feedback inhibition of A. What initially happens to H if the enzymes that catalyses B-- -> C is inhibited? What happens to A as a result? What is the final effect on A? A--> E--->G--->H.   
H shows feedback inhibition of A. What initially happens to H if the enzymes that catalyses B-- -> C is inhibited? What happens to A as a result? What is the final effect on A?

Explanation / Answer

The sequential feedback provides a control mechanism for a branched metabolic pathway. The characteristics of this pathway are;

Therefore, if the enzymatic reaction B to C is inhibited there is accumulation of H which inhibits the buildup of A.

If both the end products D and H are present in abundance this leads to build up of A which in turn inhibits the first committed step in the formation of A.

The sequential feedback provides a control mechanism for a branched metabolic pathway. The characteristics of this pathway are;

  • the end product of each branch inhibits the first enzymatic reaction of its own branch
  • there is accumulation of the last metabolite of the common pathway
  • inhibition of the common pathway if both end products are present in excess

Therefore, if the enzymatic reaction B to C is inhibited there is accumulation of H which inhibits the buildup of A.

If both the end products D and H are present in abundance this leads to build up of A which in turn inhibits the first committed step in the formation of A.