A typical cell phone, which transmits microwaves, can have an output power as hi
ID: 1695412 • Letter: A
Question
A typical cell phone, which transmits microwaves, can have an output power as high as 2.0 W.(a) Approximating the cell phone as a point source that radiates evenly in all directions, calculate the radiation intensity of a cell phone at a distance of 2.00 in. which is the approximate distance from your cell phone to your brain. Convert inches to whatever metric units you need, and give your answer in milliwatts/cm2.
(b) The U.S. Food and Drug Administration limits the radiation leakage of microwave ovens to no more than 5.0 mW/cm2 at a distance of 2.00 in. How does your answer above compare with the maximum allowable power density leaking from a microwave oven? (Answer as the ratio of cellphone power / microwave power.)
(a) Approximating the cell phone as a point source that radiates evenly in all directions, calculate the radiation intensity of a cell phone at a distance of 2.00 in. which is the approximate distance from your cell phone to your brain. Convert inches to whatever metric units you need, and give your answer in milliwatts/cm2.
(b) The U.S. Food and Drug Administration limits the radiation leakage of microwave ovens to no more than 5.0 mW/cm2 at a distance of 2.00 in. How does your answer above compare with the maximum allowable power density leaking from a microwave oven? (Answer as the ratio of cellphone power / microwave power.)
Explanation / Answer
The radiation intensity of a cell phone at a distance is I = P /(4pr^2) Here P = 2.0 W r = 2(0.0254 m) I = (2.0 W)/(4p(2(0.0254m))^2) = (61.67 W/m2)(1 mW/10^-3W)( 1m^2/10^-4cm2) = 61.67 x 10^7 mW/cm2 --------------------------------------------------------------- b) Given that intensity I = 5.0 mW/cm2 = 50.0 W/m2 distance r = 2.00 in = 2(0.0254 m) Power P = I (4pr^2) = (50.0 W/m2)(4p(2(0.0254 m))^2) = 1.6214639 W The ratio of cellphone power / microwave power is = ( 2.0 W)/(1.6214639 W) = 1.2334533Related Questions
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