4. (20) Figure 4 displays the performance of an experimental \"Pulsed Laser Prop

Question

4. (20) Figure 4 displays the performance of an experimental "Pulsed Laser Propulsion system undergoing preliminary testing.

a. (10 ) Calculate the total Impulse delivered by the system in 25 s

b. (10) If the system has a mass of 10kg and starts from rest calutate the system's velocity after 20 seconds.

BONUS (10) Assuming that the shape of the impulse burst remains similar ( a right triangle ) and the burst is spread over 10 seconds instead of 5 seconds, sketch the force vs time graph for one pulse between the 10 and 20 second marks on figure 4. What is the maximum force delivered by this modified Impulse.

Link to picture below:

http://www.pa.uky.edu/~ellis/phy211/tests211/practicetest2/page4.htm

Explanation / Answer

We know the area under Force vs time graph gives the impulse. Therefore the area of given curve is I = (1/2)(20N)(5s) + (1/2)(20N)(15s - 10s) + (1/2)(20N)(25s - 20s) = 150 N.s (b) We know that, impulse is nothing but change in the momentum So I = mv - mu I = mv - 0 I = mv At t = 20 s, the impulse is I = 100 N.s Then v = I / m = (100 N.s) / (10kg) = 10 m/s

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