With no friction and no slipping. the object of mass, m, and radius r, will cons

Question

With no friction and no slipping. the object of mass, m, and radius r, will conserve energy. Therefore. the potential energy of the ball at height, h. should equal the potential energy at the top of the loop of radius, R, plus translational and rotational kinetic energy. For the ball to complete the loop, the minimum velocity required is the one where the normal force of the loop on the ball is 0 N, so that the centripetal force is solely the force of gravity on the ball. A solid ball of mass m and radius r rolls without slipping through a loop of radius R, as shown in the figure. From what height h should the ball be launched in order to make it through the loop without falling off the track?

Explanation / Answer

mg=m(v^2/r) v^2=rg Ui=Uf+Kf mgh=mg2r+1/2mv^2 gh=g2r+1/2rg h=2.5r

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.