A bungee jumper leaps from a bridge and undergoes a series of oscillations. Assu
ID: 1698940 • Letter: A
Question
A bungee jumper leaps from a bridge and undergoes a series of oscillations. Assume g = 9.78 m/s2.
a) If a 60.0 kg jumper uses a bungee cord that has an unstretched length of 33.0 m and she jumps from a height of 50.0 m above a river, coming to rest just a few centimeters above the water surface on the first downward descent, what is the period of the oscillations? Assume the bungee cord follows Hooke's law.
b) The next jumper in line has a mass of 80.0 kg. Should he jump using the same cord? Explain.
Explanation / Answer
1/2 k (50 - 33)2 = potential energy stored inbungee cord PEB = 144.5 k m g h = 60 * 9.8 * 50 = 29400 J potential energyof jumper (to be stored in bungee cord) k * 172 = 980 m (using k * 172 / 2 = 9.8 * 50 m) ? = v(k / m) = v(980 / 289) = 1.84 /sec ? = v(k /m) for simple harmonic motion (restoring force = k x) f = ? / (2 p) P = 1 / f = 2 p / ? = 3.41 sec An 80 kg jumper cannot use the cord since m g h for thatjumper is greater than that which can be stored in the cord with an available extension of 17 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.