You hang a mass of 1.00 kg on a spring and it stretches 0.098 m. You now place t

Question

You hang a mass of 1.00 kg on a spring and it stretches 0.098 m.
You now place the mass - spring system on a horizontal frictionless surface in the equilibrium position.
You next compress the spring 0.10 m, release it and the system begins to oscillate.
We agree to start the record of time the first time the mass goes through the equilibrium position with a negative velocity.

Determine

1. Spring constant, 2. Linear frequency of the spring,3. Period of oscillation of the spring,

An exact expression for the:

 4) position of the oscillating mass at any time;     5) velocity of the oscillating mass at any time;                6) acceleration of the oscillating mass at any time;   7) force  acting on the oscillating mass at any time;      8) kinetic energy of the oscillating mass at any time;     9) potential energy of the spring at any time;       10)  total mechanical energy of the mass-spring system at any time

11. Position of the mass at t = T/4;   12) Velocity of the mass at t= T/2

13. Acceleration of the mass at T = 3T/4            

14. Position, velocity, and acceleration of the mass at t= 0.30 s

Explanation / Answer

nvm got it

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