Question: A majorette takes two batons and fastens them together in the middle a

Question

Question: A majorette takes two batons and fastens them together in the middle at right angles to make an "x" shape. Each baton was 0.80 m long and each ball on the end is 0.20 kg. (Ignore the mass of the rods). What is the moment of inertia if the arrangement is spun around an axis formed by one of the batons?

I am really lost on how to work this problem. All i have found out is that the answer is 0.064 kgm^2. Otherwise, I don't know anything esle about it.If someone could help me with this,preferably by noon tomorrow (the 22nd) I would really appreciate it! Thanks

Explanation / Answer

if the axis is passes through one of the batons the moment of inetia of masses of this baton is zero

and masses of another baton rotates about the axis

then   moment of inetia of the rorating baton with respect to axis

I = 2 m*r^2

Here r = distance between one of the masses to the axis = 0.80 / 2 = 0.4 m

m   = 0.2 kg

I =2(0.2)(0.4)^2   = 0.064 kg .m^2

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.