1) 2) Due to friction, a force of 400 N is needed to drag a wooden crate across
ID: 1701971 • Letter: 1
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Due to friction, a force of 400 N is needed to drag a wooden crate across a floor. The rope tied to the crate is held at an angle of 56digree with the horizontal. How much tension is needed In the rope to move the the crate? What work is done if the crate is dragged 25 m? A hiker carries a 20-kg knapsack up a trail. After 30 minutes, the hiker is 300 m higher than the starting point. What Is the weight of the knapsack? How much work in Joules is done on the knapsack? If the hiker weighs 600 N. how much total work is done? During the 30 min. what is the hiker's average power in watts and in kilowatts?Explanation / Answer
1) (a) Tension, F = 400 N (b) Work = F S cos theta = 400 * 25 * cos 56 = 5591.9 N 2) a) Weight, W = m g = 20 * 9.8 = 196 N b) Work, WD = W * h = 196 * 300 = 58800 J c) Weight of the hiker, W' = 600 N Total Work done, WD = ( W = W' ) * h = (600 + 196) * 300 = 238800 J d) Time, t = 30 min = 1800 s Power, P = Work / time = 238800 / 1800 = 132.67 W = 0.132 kW
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