The Ka x-ray is emitted when an electron undergoes a transition from the L shell

Question

The Ka x-ray is emitted when an electron undergoes a transition from the L shell (n = 2) to the K shell (n = 1). Use the following equations to calculate the wavelength of the Ka x-ray from a cobalt target (Z = 27), where E0 is the ground-state energy.
? = .1681 nm
(Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. nm)
EK = -(Z - 1)2(13.6 eV)
EL = -Zeff2E2
? =hc/?E

Explanation / Answer

use -(27-3)^2(13.6/4) for the 2nd equation... then solve as normal.

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