Two equally charged particles are held 3.2 times 10-3 m apart and then released

Question

Two equally charged particles are held 3.2 times 10-3 m apart and then released from rest. The initial acceleration of the first particle is observed to be 8.0 m/s2 and that of the second to be 10.0 m/s2. The mass of the first particle is 6.3 times 10-7 kg. What is the mass of the second particle? What is the magnitude of the charge of each particle?

Explanation / Answer

a) forces are equal and opposite so, m1*a1 = m2*a2 =>6.3*10^-7 * 8 = 10*m2 =>m2 = 5.04*10^-7 kg b) force = ma = 6.3*10^-7*8 = 5.04*10^-6N kq^2/r^2 = 5.04*10^-6 =>9*10^9*q^2/(3.2*10^-3)^2 = 5.04*10^-6 =>q = 7.58*10^-11 C

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