7. A baseball (m = 149 g) approaches a bat horizontally at a speed of 40.2 m/s (

Question

7. A baseball (m = 149 g) approaches a bat horizontally at a speed of 40.2 m/s (90 mph) and is hit straight back at a speed of 45.6 m/s (102 mph). If the ball is in contact with the bat for a time of 1.10 ms, what is the average force exerted on the ball by the bat? Neglect the weight of the ball, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction. (NOTE: I used to be a high school baseball coach, and one fundamental that I stressed to my players was following through with their swings. A follow-through allows the bat to spend more time in contact with the ball. Plug in a higher value for contact time than the one listed, and see why following through is important!) (Chapter 7)
a. -11 600 N
b. -9820 N
c. -5420 N
d. -10 800 N
e. -6180 N


Totally lost.. please help

Explanation / Answer

Impulse=((kg*voi)²(kg*vof)²-(2*kg*voi*kg*vof*cos()))

Impulse/contact time=mag of avg force in N

a) -11600 Nshould be -11622 N

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