Now the charges Q1= 1.22x10-6 C and Q2= -2.65 x10-6 C are fixed at their positio

Question

Now the charges Q1= 1.22x10-6 C and Q2= -2.65 x10-6 C are fixed at their positions, distance 0.290 m apart, and the charge Q3= 3.33 x10-6 C is moved along the straight line. For what position of Q3 relative to Q1 is the net force on Q3 due to Q1 and Q2 zero? Use the plus sign for Q3 to the right of Q1.

And in the previous problem that is related to this one I found that force on Q2 from Q1 and Q3 is 2.248N. I am not sure if I use this force in this problem or not.

I am having a hard time solving for this problem, thank's for the help...

Explanation / Answer

you can see that Q1

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.