14. A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3

Question

14. A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00m tall on the top of the head. It bounces back oup 1.50 m before falling to the ground. If the mass of the coconut is 2.00kg, calculate the PE of the coconut relative to the ground at each of the following sites:

a. while it is still in the tree
b. when it hits the bystnader on the head
c. when it bounces up to its max height
d. when it lands on the ground
e. when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole.

gravity= 10 p=w/t W= fxd Mechanical Efficiency= Wo/Wi x 100
PE= mgh
KE = 1/2mv^2

Explanation / Answer

Taking the PE at gound = 0

a)pE at tree = mgh = 2(10)(12) = 240 J

b)At the head of bystander = 2(10)3= 30J

c)bounces to max height = 2(10)(3+1.5)= 90 J

d)at ground = 0 J

e) at the bottom of ground hole= 2(10)(2.5)= 50 J

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