A constant-volume gas thermometer is calibrated in dry ice (that is, evaporating

Question

A constant-volume gas thermometer is calibrated in dry ice (that is, evaporating carbon dioxide in the solid state, which has a temperature of -80.0°C) and in boiling ethyl alcohol (78.0°C). The two pressures are 1.064 atm and 1.932 atm.

(a) What Celsius value of absolute zero does the calibration yield? (Express your answer to the nearest 0.01°C.)


(b) What is the pressure at the freezing point of water?
atm

(c) What is the pressure at the boiling point of water?
atm

Explanation / Answer

We know that P = m T + Po Where m = slope Slope m = (1.932 - 1.064) / (78 - (-80)) = 0.00549367089 Therefore p = 0.00549367089 T + po ------------------------------------------------------------------------------------------------------- What value of absolute zero does the calibration yield 1.932 =0.00549367089 * 78 + po ==> po = 1.50349367 atm So that p = 0.00549367089 T + 1.50349367 We need to find the temp when P = 0 So we have 0 = 0.00549367089 T + 1.50349367 ==> T = -273.677419 oC ----------------------------------------------------------------------------------------------------- what pressures are at the freezing and boiling points of water? At freezing point T = 0 oc ==> P = 1.50349367 atm At boiling point T = 100 oC ==> P = 0.00549367089 * 100 + 1.50349367 = 2.05286076 atm

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