A: A nonconducting solid sphere of radius 2.10 cm carries a uniformly distribute

Question

A: A nonconducting solid sphere of radius 2.10 cm carries a uniformly distributed positive charge of 7.40×10-9 C. Calculate the magnitude of the electric field at a point 1.30 cm away from the center of the sphere.

hint: This distance is still within the sphere. You have to integrate the charge up to this distance.

B: Calculate the magnitude of the electric field for a conducting sphere at a point 3.20 cm away from the center of the sphere.

hint: Again Gauss's Law. What do you know about the field outside a spherically symmetric charge distribution.

Explanation / Answer

the charge density . ?=Q/V=Q/(4piR^3/3)=1.9e-4(C/m3). so the net charge of a sphere which has the radius of 1.3cm inside the sphere. Q=1.9e-4*4pi*1.3e-2^3/3=1.76e-9(C) -- E*4piR^2=Q/epsilon0. so E=9.3e4(V/m) ---------------------- we still have E=Q/epsilon0*4piR^2=kQ/R^2

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