<p>A ball rolls on a circular track of radius 0.66 m with a constant angular spe

Question

<p>A ball rolls on a circular track of radius 0.66 m with a constant angular speed of 1.3 rad/s in the counterclockwise direction.<br />Part A: If the angular position of the ball at t=0 is &#952;=0, find the x&#160;component of the ball's position at the time 2.6 s. Let &#952;=0 correspond to the positive x direction. <br />Part B: Find the x component of the ball's position at the time 5.0 s. <br />Part C: Find the x component of the ball's position at the time 7.5 s.&#160;</p>

Explanation / Answer

at t=2.6 the angular position is phi = 1.3*2.6=3.4(rad). so x-component. x=0.66*cos(3.4)=-0.64(m) at t=5s. phi = 5*1.3 = 6.5(rad). x-component. x=0.66*cos(6.5)=0.64(m). at t=7.5s. phi = 7.5*1.3=9.75. x-component. x=0.66*cos(9.75)=-0.63(m)

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