The tube of a Geiger counter consists of a thin conducting wire of radius 0.0012
ID: 1707805 • Letter: T
Question
The tube of a Geiger counter consists of a thin conducting wire of radius 0.00125 cm stretched along the axis of a conducting shell of radius 1.25 cm ?see figure). The wire and the cylinder have equal and opposite charges of 7.1 times 10-10 C disturbed along their length of 8.6 cm. Find a formula for the electric field in the space between the wire and the cylinder, pretend that the electric field is that of an infinitely long wire and cylinder. What is the magnitude of the electric field at the surface of the wire? A thin wire stretched along the axis of a cylindrical conducting shell. E =Explanation / Answer
Both wire and cylinder are conductors the charges resides on their surfaces The electric field at a point which is lies between the cental wire and the cylinder let us constriuct a gaussian surface of radiues r with respect to tht point Applying gauss law electric flux = 2 *r L *E = q_enclosed /epsilon epsilon = 8.85*10^-12 N.m^2 /C^2 Here L = length of the wire , The electric field at that point E = q_enc /2 *r L q_enl = charge of the conducting wire = +7.1*10^-10 C The direction of electric field way from the wire ----------------------------------------------------- The electric field at the surface of the wire here r = radius of the wire = 1.25*10^-5 m Electric field E = q_enc / 2*rL *epsilon = (7.1*10^-10 C ) / 2(1.25*10^-5 m)(0.086m)(8.85*10^-12 N.m^2 /C^2) E = 1.18*10^7 N/C i am unable to see the charge charge given plz check itRelated Questions
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