A projectile was fired from the edge of a 15.0 m high cliff with a velocity of 8

Question

A projectile was fired from the edge of a 15.0 m high cliff with a velocity of
8.00 m/s b 30.0° up from horizontal.
a) Calculate the projectile’s initial horizontal velocity. (Vector diagram required.)
b) Calculate the projectile’s initial vertical velocity. (Vector diagram required.)
c) How long did it take the projectile to reach its maximum altitude?
d) How high did the projectile rise?
e) What was the projectile’s horizontal velocity 0.600 seconds after it was fired?
f) Calculate the projectile’s vertical velocity 0.600 seconds after it was fired.
g) Calculate the projectile’s velocity 0.600 seconds after it was fired. (Vector diagram
required.)
h) Calculate the projectile’s position 0.600 seconds after it was fired. (Vector diagram
required.)

Explanation / Answer

vo=8 m/s==>vox=vo*cos(30º)=6.93 m/s==>voy=vo*sin(30º)=4 m/s

a) vox=6.93 m/s

b) voy=4 m/s==>voy/g=0.41 s

c) 0.41 s==>max ht=15 m+voy²/(2*g)=15.82 m

d) ht from ground level is 15.82 m

e) vox is constant from the entire flight

f) vy=voy-g*t=4 m/s-9.8*0.6 s=-1.88 m/s

this program will not let me draw the vector diagram

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