The aircraft wing from problem 6 ( i will put at bottom) experiences temp. extre

Question

The aircraft wing from problem 6 ( i will put at bottom) experiences temp. extremes that span 210 deg. C. The component for the wing will have a length of exactly 3 meters. Testing indicates that the aircraft wing will remain stable only if the component never expands to a length larger than 3.017 meters. If the component is made from the metal alloy in question, will it meet this requirement?

6. ( this is a sep post but need part of to answer the question above)An unknown metal alloy is being tested to discover its thermal properties to see if it is suitable for use as a component in an aircraft wing. The alloy is formed into a bar measuring 1 meter in length, and is then heated from its starting temp. of 30 deg. C to a final temperature of 100 deg. C. The length of the heated bar is measured to be exactly 1.002 meters in length. what is the coefficient of thermal expansion of the alloy?

Explanation / Answer

           (a)                    temparature difference = t = 210 oC                              intial lengh = Lo = 3 m                               final lenght = L = 3.017 m                               change in lenght = L = 0.017 m               coefficient of thermal expansion of the alloy = = L - Lo / L o ( t)                                                                                          = 0.017 / 3 (210)                                                                                                                                                                                 = 2.698 * 10-5 / oC    (b) temparature difference = t = 70 oC                              intial lengh = Lo = 1 m                               final lenght = L = 1.002 m                               change in lenght = L = 0.002 m               coefficient of thermal expansion of the alloy = = L - Lo / L o ( t)                                                                                           = 0.002 /1 (70)                                                                                             = 2.857 * 10 -5 / oC                                            intial lengh = Lo = 1 m                               final lenght = L = 1.002 m                               change in lenght = L = 0.002 m               coefficient of thermal expansion of the alloy = = L - Lo / L o ( t)                                                                                           = 0.002 /1 (70)                                                                                             = 2.857 * 10 -5 / oC              

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