In the formula for calculating the block shear strength of bolt connection, i.e.

Question

In the formula for calculating the block shear strength of bolt connection, i.e., Eq. 3.9.5 on the text book, it contains 0.6 F_0. What is physical meaning of 0.6 F_s? If bolt diameter is d_0 = 1.5", what is the typically used spacing between bolts in the bolt connection? For a plate subject to tension load, the design tension is T_v = 190 kips, it is found that the nominal tension capacity of the plate is T_v = 200 kips and the corresponding strength reduction factor for the tension failure mode phi =0.9, to determine whether the plate can resist the load When designing a weld connection for two plates, what types of failure modes should you consider and exam (name all possible failure modes)? Determine the design connection capacity or design strength phi Tn of the following bolt connection. The bolt used in connection is 1 -in. diameter A325-X bolt and total four bolts are used. All plate is A36 dimension is A3/16" times 7" plate (Fy=36 ksi and Fu=58 ksi). You need to exam all possible failure modes (for example, bolt shear failure. plate bearing failure, plate tension failure, or plate shear block failure) and draw the failure path

Explanation / Answer

5) 0.6*Fu represents net section fracture strength on shear path

6) As per AISC J3.3 minmum is 2.67d and preferrably 3*d.

Hence the typically used spacing for 1.5 inch bolt diameter is 3*d =3*1.5 = 4.5 inch

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