I need help with problem 42. I think their answer for Reaction @ joint E is inco

Question

I need help with problem 42. I think their answer for Reaction @ joint E is incorrect.

litiu lou adCB able. IY W is 2000 1b, what is the pin reaction at A on the rod AB? What is the tension in the cable? Ans , Ah 3460 1b, Au 2000 1b, T-3460 1b equilibrium 41. In the adjacent figure, the forces are 2K 5K 4K shown acting on the beam divided into one foot intervals. The loads are in kips. Determine the reactions at A and B. Ans. A 1.65 K 75° 90° 80 60° Determine the r A, 4.60 K B8.71 K 2 Bea ED is loaded as shown. The beam is pin connected to the wall at E. At D an 8 inch di- ameter pulley is attached through frictionless bearings to the beam. A rope passes around the pulley and is connected to A and B vertically above the extremities of the hori- zontal diameter of the pulley. De- termine the pin reaction at E, and the tension in the rope. 90° 60° Be = 51 T = 74.4 lb 100 lb 200 lb

Explanation / Answer

Since there is a horizontal force component as well, acting on the beam, this horizontal force will be resisted by pin at E because support at D cannot resist horizontal force

Horizontal force on beam= 200cos60=100lb(towards left)

Reaction force exerted by support at E on beam= 100lb(towards right)

Vertical reaction at E=124.41lb(as correctly calculated by you)

Therefore,resusltant force at support E=sqrt(100²+124.41²)=160lb

Reaction force is rightly noted

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