To complete a new section of the Florida Turnpike, 15-inches of limerock base ma

Question

To complete a new section of the Florida Turnpike, 15-inches of limerock base material must be placed over a 100-foot wide section of pavement that will be 25 miles long. How much limerock is needed? What units would be simplest for you to use to present this number? If you are hauling the material to the roadway using trucks that hold 20 cubic yards of material, how many trucks will you need? Note: limerock is a good road base material, with adequate drainage, strength and stiffness properties.

Explanation / Answer

Thickness of limestone (t) = 15" = 1.25'

Width of pavement (w) = 100'

Length of the pavement (l) = 25 miles = 132000"

Volume of limestone required = l x w x t = 1.25' x 100' x 132000'

= 16500000ft3

=611111.1 Cubic yards

Capacity of Truck = 20 cubic Yards.

No. of trucks required = 611111.1 / 20 = 30556 Trucks

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