2-1 The following test results were obtained for three treated wastewater efflue

Question

2-1 The following test results were obtained for three treated wastewater effluent samples. Check the accuracy of the analytical measurements for one of the waters (to be selected by instructor). Do you suspect that a constituent of significance has been neglected? If so, is it a cation or anion? Concentration, mg/L Wastewater sample no. Concentration, mg/L Wastewater sample no Cation Ca2* Mg? Na 2 Anion 2 121.3 76.0190. HCO5 280.0 128.2 260.0 64.0 37.2 440.4 35.1 30.0 36.2 27.2 229 75.2C 18.7 84.1 116.0 61.0 15.6 240.0 12.0 2.0 Fe2+ 0.2 CO3

Explanation / Answer

we can see in all three tests milliequivalents of Anoin is less then Cation but in case of 3 the difference is more in case of 1 is the difference is small and in case of 2 it is very small. Hence in case of 3 and 1 ( especially 3) constituents of Anion significantly has been neglected.

thanks

Cation 1 2 3 Equilent wt mili equivlent
of Cation 1 2 3 Ca2+ 121.3 76 190.2 20 6.065 3.8 9.51 Mg2+ 36.2 27.2 84.1 12 3.016667 2.266667 7.008333 Na+ 8.1 22.9 75.2 11 0.736364 2.081818 6.836364 K+ 12 18.7 5.1 39 0.307692 0.479487 0.130769 Fe2+ 0 2.1 0.2 28 0 0.075 0.007143 total miliequivlent of Catain= 10.12572 8.702972 23.49261 Anion 1 2 3 Equilent wt mili equivlent
of Cation 1 2 3 HCO3- 280 128.2 260 61 4.590164 2.101639 4.262295 SO42- 116 240 64 48 2.416667 5 1.333333 Cl- 61 37.2 440.4 35 1.742857 1.062857 12.58286 NO3- 15.6 2 35 62 0.251613 0.032258 0.564516 CO32- 0 0 30 30 0 0 1 Total miliwquivlent of anain = 9.001301 8.196755 19.743

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