(6 points) 426 pounds of 1,2,3,4-tetramethylcyclobutene completely decomposes in
ID: 1711929 • Letter: #
Question
(6 points) 426 pounds of 1,2,3,4-tetramethylcyclobutene completely decomposes in the presence f molecular oxygen, such that the final products will be carbon dioxide and water. a) Show the chemical reaction that occurs (including balancing of the equation) b) Show the molecular weights of each constituent c) How much CO2 (kg), if any, is produced from the reaction? d) How much oxygen (kg), if any, is required to complete the reaction? e) Show how you would calculate the reaction constant for ethanol. f) Determine how many liters of air are required for ThOD at 35°C. Assume air is 20.9% oxygen. 6. Definitions - what do these mean and what do they relate to (20 pts)? For example, SDWA Safe Drinking water Act and it relates to water quality in the water distribution system and at people's taps in their houses. Not all are Laws ESA = CAA = PPE = CWA- MSDS- CERCLA NEPA = EHS SWDA- RCRA =Explanation / Answer
a)The chemical formula for 1 2 3 4-tetramethylcyclobutene is C8H14
The balanced equation of combustion of C8H14 is
2C8H14 + 23O2 --> 16CO2 + 14H2O
b) Molecular mass of C8H14 is 110gm = 0.2425 pound
Molecular mass of O2 = 32gm=0.0705 pound
Molecular mass of CO2 = 44gm=0.097 pound
Molecular mass of H2O=18gm=0.0397 pound
c)Per chemical reaction shown, 0.485 lb of chemical produces 1.552 lb of CO2
429 lb of chemical will produce (1.552/0.485)*429=1372.8 pounds = 622.691 kg of CO2
d)0.485 lb of chemical needs 1.6226 pounds of oxygen
429 pounds of chemical needs (1.6226/0.485)*429=1435.25 pounds = 651.018 kg of oxygen
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