The 50\'- 0\" girder below is connected to the column with simple connections an

Question

The 50'- 0" girder below is connected to the column with simple connections and supports a factored, uniform load, w a) If the girder shown is a W21x48, A992 steel, and continuously laterally supported at the compression flange, Using AISC part 16 and the design tables check the adequacy of the section if the girder b) Using AISC part 16 and the design tables determine the maximum wu that the girder shown carn c) Using AISC part 16 and the design tables determine the maximum w that the girder shown car Note: Check pM, only and assume that the girder is safe in shear and deflection. supports an ultimate uniform load, ww 1.27 k/ft. support if it is made of W24x55 A992 steel and laterally supported at the 20'- 0" points. support if it is made of W24x55 A992 steel and laterally unsupported over the entire length 2 50-0 20'-0" 10'-0" FACTORED UNIFORM LOAD, wu

Explanation / Answer

4(T1+T2+T3+T4) = 2(T1+T2+T3+T4)+370-170*3+160*2;

2(T1+T2+T3+T4) = 180;

(T1+T2+T3+T4) = 90;

NOW;

4T1 + 170 = (T2+T3);

(T1+ 4T1 + 170 +T4) = 90;

(5T1 +T4) = -80; eq 1

Now,

4T4 + 10 = (T2+T3);

(T1+ 4T4 + 10 +T4) = 90;

(T1+ 5T4 ) = 80; eq 2

Eq 1 + eq2;

T1+T4 = 0;

so,

T4 = 20;

T1 = -20;

So now,

T2 + T3 = 90;

Also;T3 = (T1+T4+370-170)/4

T3 = 50;

T2 = 40;

Ans

T1 = -20;

T2 = 40;

T3 = 50;

T4 = 20;

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