Some data are supplied as follows ULS 1.2G+1.5Q Slab thickness is 150mm = 2450kg

Question

Some data are supplied as follows ULS 1.2G+1.5Q Slab thickness is 150mm = 2450kg/m2 | Q-3kPa a) Calculate the self-weight of the slab (kPa) and ULS load (kPa) (2 marks) b) Determine and sketch ONE suitable lower bound distribution of loading for design purposes. Clearly indicate the percentages of loading to be taken in the different directions. Clearly indicate the location and dimensions of any strong bands you may have chosen. INCLUDE THE ENTIRE 7m x 5m SLAB. Fully dimension your (5 marks) sketch c) For the distribution chosen in part b), draw fully dimensioned loading diagrams (ULS and in kN/m) for ALL sections of the 7m x 5m slab. Use typical 1m wide strips. Show the location of all support reactions. Maximum moments and support (10 marks) reaction values are not required d) With the aid of a sketch briefly explain Poisson's effect for a slat (3 marks) 5000 mnm 1000 mnm FIGURE 4.1 5000 mnm LETFrrTT|C 1000 mm

Explanation / Answer

1. Self wt of slab= L*B*Thickness*2450=12,862.5 kPa,

Since L/B ratio greater than one hence two way slab.

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.