CONS 3015 PROBLEM 4-D DEFLECTION PROBLERMS NO. 1 Cakculate the deflection of a p
ID: 1714189 • Letter: C
Question
CONS 3015 PROBLEM 4-D DEFLECTION PROBLERMS NO. 1 Cakculate the deflection of a plywood form board: Given Data: Flat-horizontal- three (3) span continuous use in problems No.1, 3, 4, 5,6,7&8 Plywood 5/8" sanded, Class I, BB Plyform-Table 4.13 Plywood is laid in its strong direction. Supports are spaced at 24" c/c Loading -8 "concrete and self-weight of plywood. NO. 2 Calculate the deflection of a single span use of the plywood in the above condition. No. 3 Recalculate the deflection required in Problem NO. 1 using " thick plywood NO. 4 Recalculate the deflection required in Problem No. 2 using %" thick plywood NO. 5 What is the span-to-deflection ratio of Problem NO. 1? NO. 6 What is the span-to-deflection ratio of Problem NO. 27 NO. 7 What is the span-to -deflection ratio of Problem NO. 3? NO. 8 What is the span-to deflection ratio of Problem NO. 4?Explanation / Answer
1) Wt of 5/8" plyboard = 1.9lb/ft2
Wt of concrete = (8/12)*150 = 100lb/ft2 (Assuming self weight of concrete is 150lb/ft3)
udl assuming 1 feet width of board = 1.9+100 = 101.9lb/ft = 8.492 lb/in (w)
Deflection = 0.0069wl^4/(EI) = 0.0069*8.492*24^4/(EI) = 19440.35/EI
Since the plywood is lain in the stronger direction, I = 0.13in4 as per the table. However since E is unavailable, deflection cannot be calculated.
2) For a single span beam (i.e. simply supported beam), deflection = (5/384)*(wl^4)/(EI) = (5/384)*(8.492*24^4)/(EI)
deflection = 36685.44/EI. I is as in problem 1. However since E is unavailable, deflection cannot be calculated.
3) Weight of 1/2" thk board = 1.5lb/ft2
Therefore udl, w = 8.458lb/in2
As calculated for problem 1, deflection = 19362.51/EI
I = 0.077in^4 ( as per table for ply laid on stronger side). E unavailable.
4) Deflection as calculated for Problem 2 = 36538.56/EI
To calculate the span to deflection ratio in problems 5 to 8, span is talen as 24" and deflections are as calculated above. If E value is available, the ratios can be calculated as span/deflection.
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