[closed loop control and feedback polarity] Input Potentiometer Angle Input Pot
ID: 1716774 • Letter: #
Question
[closed loop control and feedback polarity]
Input Potentiometer Angle
Input Pot Voltage (Blue)
Output Pot Angle
Output Pot Voltage (Yellow)
Power Amp Input signal (Orange)
0
0
22
-.18V
.179
30
-.214
-174
-.026V
.178
60
.258
-34
-.427
.175
90
.457
-64
-.629
.177
120
.664
-90
-.839
.201
-60
.415
86
-.590
.174
-120
.839
142
-1.029
.178
Input Pot Setting
-120/240
-90/270
-60/300
-30/330
0/360
30
60
90
120
Output shaft
264 degree
294
322
354
24
54
82
112
142
What is the input (physical variable) of this control system?
The input of this control system is an angle.
What is this system controlling?
This system is controlling the current.
Define error signal?
A to
What was the approximate power amp input voltage for this system and why?
Why the system goes into oscillation?
Is this system stable or unstable?
The system is stabled.
Explain what general principals are demonstrated regarding closed-loop systems? Why we use negative feedback in control systems?
Why positive feedback is undesirable in control systems?
Explain why the direction of motor direction in practical 3 is opposite that indicated in Table 4-1.
Which part of this system produces the error voltage?
Which system component converts the motor position to voltage?
Input Potentiometer Angle
Input Pot Voltage (Blue)
Output Pot Angle
Output Pot Voltage (Yellow)
Power Amp Input signal (Orange)
0
0
22
-.18V
.179
30
-.214
-174
-.026V
.178
60
.258
-34
-.427
.175
90
.457
-64
-.629
.177
120
.664
-90
-.839
.201
-60
.415
86
-.590
.174
-120
.839
142
-1.029
.178
Explanation / Answer
In negative feedback systems, the output value is subtracted from the reference input. The effect of negative feedback is to reduce the gain. Negative feedback produces stable output and hence improves the stability of the system.
Positive feedback is undesirable in control systems because with positive feedback, if the output is more, it is again increased and if the output is less, it is made lesser. Hence, the positive feedback does not result in a stable output.
The error voltage is determined by the output minus the reference input.
The forward system component converts the motor position to voltage.
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