A minimum mass symmetric (area of member 1 is the same as member 3) three-bar tr

Question

A minimum mass symmetric (area of member 1 is the same as member 3) three-bar truss is to be designed to support a load P as shown. The following notation may be used: Pu=P*cos(theta), Pv=P*sin(theta), A1 = cross-sectional area of member 1 and 3, A2 = cross-sectional area of member 2.

The members must not fail under the stress, and deflection at node 4 must not exceed 2 cm in either direction. Use Newtons and millimeter as units. The data is given as P=50 kN; theta=30 degrees; mass density rho = 7850 kg/m^3; modulus of elasticity, E=210 GPa; allowable stress sigma_a= 150 MPa. The design variables must also satisfy the constraints 50<= Ai <= 5000 mm^2.

Explanation / Answer

Sorry the question is incomplete as Intial design varible values of A1 and A2 are not given.

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