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Create the following matrix M: M= Use the matrix M to: Create a five element row

ID: 1719808 • Letter: C

Question

Create the following matrix M: M= Use the matrix M to: Create a five element row vector named MatA that contains the elements of the second row of M. Create a three element row vector named MatB that contains the elements of the fourth column of M. Create a ten element row vector named MatC that contains the elements of the first and second rows of M. Create a six element row vector named MatD that contains the elements of the second and fifth columns of M. Create these 3 arrays by using either commas or line space: A= B= C=[49.5 49.1875 48.875 48.5625 48.25 47.9375 47.625 47.3125 47] Replace the last 4 columns of the 1^st and 4^th rows of A with the last 4 columns of the 1^st and 3^rd rows of B. Replace the first 4 columns of the 2nd row of A with the 2nd, 4th, 6th, 8^th elements of C. Replace the 2^nd and 3^rd rows of the last column of A with the last 2 rows of the 1^st column of B.

Explanation / Answer

Background : Any Matrix M is a rectangular array consisting of m rows and n columns (rows are horizontally laid out and columns are vertically laid out ).

For instance, the Matrix M given in Problem 1 consists of 3 rows and 6 columns.

                    The Matrix A given in Problem 2 consists of 6 rows and 5 columns

                    The Matrix B given in Problem 2 consists of 3 rows and 6 columns

                    The Matrix C given in Problem 2 consists of 1 row and 9 columns.

Problems 1 and 2 dont involve any calculation. It is just replacing appropriate blocks of a given matrix A by the blocks (maintaining the same number of rows and columns) by another matrix B.

Solution to Problem 1:

(a) MatA = [12   6   34   0   5]

(b) MatB = [ 11 0 41]

(c) MatC = [ 6 43 2 11 87 12 6 34 0 5]

(d) MatD = [43 6 18 11 0 41]

Solution to Problem (2):

(a) The last 4 columns of the first and 4th rows of A are

                                               2          3            4              5

                                               14         15         16            17

This block needs to be replaced by the last 4 columns of the 1st and 3rd rows of B, which consists of

                                                17    23     29     35

                                                 65    70    75    80

Thus the new (transformed matrix ) will look like

1

17

23

29

35

5

6

7

8

9

9

10

11

12

13

13

65

70

75

80

17

18

19

20

21

21

22

23

24

25

                                   

                                               

(b) The first 4 columns of the 2nd row of A are

                                    5      6     7     8

This needs to be replaced by the 2nd, 4th , 6th and 8th elements of C. It is clear that the modified matrix is given by

1

2

3

4

5

49.1875

48.5625

47.9375

47.3125

9

9

10

11

12

13

13

14

15

16

17

17

18

19

20

21

21

22

23

24

25

(c) The 2nd and 3rd rows of the last column of A consist of

                              9

                              13

They need to be replaced by the last 2 rows of the 1st column of B , consisting of

                             27

                             55

resulting in the transformed matrix

1

2

3

4

5

5

6

7

8

27

9

10

11

12

55

13

14

15

16

17

17

18

19

20

21

21

22

23

24

25

                            

1

17

23

29

35

5

6

7

8

9

9

10

11

12

13

13

65

70

75

80

17

18

19

20

21

21

22

23

24

25

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