2. A 300 g mass movingat 7.5 cm/s eastward collides with a 500 g mass moving at5
ID: 1721674 • Letter: 2
Question
2. A 300 g mass movingat 7.5 cm/s eastward collides with a 500 g mass moving at5.0
cm/s westward on ahorizontal low friction surface. The two masses stick togetherafter
the collision. What arethe velocities of each mass after the collision?
3. The collision inQuestion 2 lasted for 0.11 sec. Calculate the force that acted oneach
mass.
4. For the same twomasses and initial conditions as in Question 2,
a) What are the finalvelocities if the collision is elastic this time?
b) Calculate the force that acted oneach mass.
Explanation / Answer
The cramster rules say only one question per post, so i'llanswer two of these to be nice..Rate fairly. 1-dimensional collision; the masses stick together and movewith each other after the collision... This inelastic collision is modeled by : mV1 + MV2 = (m+M)V' where V' = common velocity after collion.. m = 300 g = .3 kg 7.5 cm/s eastward = .075 m/ s eastward.. M = 500 g = .5 kg 5.0 cm / s westward = - .05 m/s (keeping eastward positive) plug these values in.. (.3)(.075) + (.5)(-.05) = (.5+.3) V' V' = -3.125 x 10^ -3 since east was positive, thisdirection is west because it's negative.. Momentum is also defined as.. P = FT Pf - Pi for mass M = MVf - MVi = M (Vf - Vi ) = (.5)( (-3.125 * 10 ^ -3) - -.05 ) = F = .023 N , direction of force is EASTWARD(positive) P = FT Pf - Pi for mass m (.3)((-3.125 * 10 ^-3) -.075) =Related Questions
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