How fast are the ions moving when they emergefrom the velocity selector? Singly

Question

How fast are the ions moving when they emergefrom the velocity selector? Singly ionized (one electron removed) atoms are accelerated andthen passed through a velocity selector consisting of perpendicularelectric and magnetic fields. The electric field is151 V/m and the magneticfield is 3.1310?2 T. The ions next enter auniform magnetic field of magnitude1.7510?2 T that is orientedperpendicular to their velocity. How fast are the ions moving when they emergefrom the velocity selector? v =4820 m/s Correct If the radius of the path of the ions in thesecond magnetic field is 17.1 cm, what is their mass?

Explanation / Answer

   radius of charged particle in magneticfield   r   =   m* v / B * q    here   r   =   17.1   cm   =   0.171   m,   v   =   4820   m/s,   B   =   Strengthof magnetic field   =   1.75 *10-2   T    charge onparticle   q   =   e   =   1.6* 10-19   C    =>   m   =   B* q * r / v   =   1.75 *10-2 * 1.6 * 10-19 * 0.171 /4820   =   9.93 *10-26   kg

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.