Two equal charges enter a magnetic field oriented along thepositive z-axis. The
ID: 1722481 • Letter: T
Question
Two equal charges enter a magnetic field oriented along thepositive z-axis. The particles are initially at theorigin. Charge A has a velocity vA = v0 i + v0 j + v0 k and chargeB has a velocity vB = 2v0 i +
v0
2
j +
v0
2
k . In
both cases the path of the motion will be a helix. What will be thedifference in the patterns of motion?
A) The helix for B will have wider circles closer to eachother.
B) The helix for B will have same-size circles as A, but spreadfurther apart.
C) The helix for B will have wider circles spread furtherapart.
D) The helix for B will have same-size circles as A, but groupedcloser to each other.
E) Both helixes will look the same.
Explanation / Answer
The force on particles is F=q*v*B and on the otherhand centripital force is defined as F= mv2/r In helix these 2 forces are equal which gives us r=(mv)/(qB) So since 2nd one has bigger speed it will have bigger helixradius and more apart. Answer is C. I hope this helps...Related Questions
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