(a) If m 1 = 24 kg, find m 2 such that there is no angular accelerationof the wh
ID: 1722871 • Letter: #
Question
(a) If m1 = 24 kg, findm2 such that there is no angular accelerationof the wheels.1 kg
(b) If 12 kg is gently added to the top of m1,find the angular acceleration of the wheels.
2rad/s2
Find the tension in the rope holding m1.
3 kN
Find the tension in the rope holding m2.
4 kN Two objects are attached to ropes that are attached to wheels on acommon axle as shown below. The two wheels are glued together sothat they form a single object. The total moment of inertia of thetwo wheels is 41 kg m^2. The radii of the wheels are R1 =1.1 m and R2 =0.30 m. (a) If m1 = 24 kg, findm2 such that there is no angular accelerationof the wheels. 1 kg (b) If 12 kg is gently added to the top of m1,find the angular acceleration of the wheels. 2rad/s^2 Find the tension in the rope holding m1. 3 kN Find the tension in the rope holding m2. 4 kN
Explanation / Answer
given moment of inertia two wheels = I = 41kgm2 radil of wheells = R1 =1.1m R2 = 0.30m from the diagram net = m1gR1 -m2g R2 = 0 solving for m2 =m1 R1/R2 m2 = 24kg (1.1m/0.3m ) = 88kg b) applying newton seconed law to objective and pully Fx = m1g - T1 =m1a --------(1) 0 = T1R1 - T2 R2 = I0 ------(2) and Fx = T2 -m2g = m2a ------(3) eleminate ,a , in favour of inewquations eq 1 and 3 solve for T1 andT2 T1 = m1 (g - R1) T2 = m2 (g+R2 ) subsitue T1and T2 eq 3 then = (m1 R1 -m2 R2) g/m1R12 + m2R22 + I0 plug in values = ----------- plug in values = -----------Related Questions
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