This problem is really kicking my butt. I\'ve tried twice, but to noavail. I\'m

Question

This problem is really kicking my butt. I've tried twice, but to noavail. I'm sure my process somewhere is wrong, but I'm not surewhere..... i got the volume of the cylinder to be 5.67m3though that may be incorrect, I used 10cm as cylinder height. Iended up with the equation 1000kg/m3 x5.6745m3 x 9.8 m/s2 ........ please help mefigure this one out.

A cylindrical metal can with a radius of 4.25 cm is floatingupright in water. A rock is placed in the can, causing it to sink0.0238 m deeper into the water. What is theweight of the rock?

Explanation / Answer

radius=0.0425 m volume of water displaced when it sunk 0.0238 mdeeper=*0.04252*0.0238=1.35*10-4m3 density of water=1000 kg/m3 mass of waterdisplaced=density*volume=1000*1.35*10-4=0.135 kg weight of the rock=weight of water displaced=0.135*9.8=1.324kg(ans)

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