A satellite is in circular orbit 230 km above thesurface of the Earth. It is obs

Question

A satellite is in circular orbit 230 km above thesurface of the Earth. It is observed to have a period of 89 min.What is the mass of the Earth? (The mean radius of Earth is6.38*10^6m) I know the 2 equations are Mass ofplanet=4^2*r^3/T^2G and r=Rth, but i cant figure this out A satellite is in circular orbit 230 km above thesurface of the Earth. It is observed to have a period of 89 min.What is the mass of the Earth? (The mean radius of Earth is6.38*10^6m) I know the 2 equations are Mass ofplanet=4^2*r^3/T^2G and r=Rth, but i cant figure this out

Explanation / Answer

h = 2.30*105 m, T = 89 min = 89*60 s, R =6.38*106 m, find M r R + h GmM/r2 = mv2/r =m(2r/T)2/r GM = r*(2r/T)2 M = r*(2r/T)2/G =(2/T)2r3/G = 5.99*1024 kg

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.